a) $$8 – x = 2$$
b) $$\frac{1}{8} + \frac{1}{x} = \frac{1}{2}$$
c) $$\frac{{500}}{8} + \frac{{500}}{x} = 500$$
d) $$\frac{x}{2} + \frac{x}{8} = 1$$
Answer: b
Explanation: Number of envelopes addressed by first machine in 1 minute
$$ = \frac{{500}}{8}$$
Number of envelopes addressed by second machine in 1 minute
$$ = \frac{{500}}{x}$$
Number of envelopes addressed by both machine in 1 minute
$$\eqalign{
& {\text{ = }}\frac{{500}}{2} \cr
& \frac{{500}}{8} + \frac{{500}}{x} = \frac{{500}}{2} \cr
& \frac{1}{8} + \frac{1}{x} = \frac{1}{2} \cr} $$
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