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A and B can do a job together in 7 days. A is 1*3/4 times as efficient as B. The same job can be done by A alone in :

a) $$9\frac{1}{3}$$  days
b) 11 days
c) $$12\frac{1}{4}$$  days
d) $$16\frac{1}{3}$$  days

Answer: b
Explanation:
$$\eqalign{ & \left( {{\text{A’s}}\,{\text{1}}\,{\text{day’s}}\,{\text{work}}} \right){\text{:}}\left( {{\text{B’s}}\,{\text{1}}\,{\text{day’s}}\,{\text{work}}} \right) \cr & = \frac{7}{4}:1 = 7:4 \cr & {\text{Let}}\,{\text{A’s}}\,{\text{and}}\,{\text{B’s}}\,{\text{1}}\,{\text{day’s}}\,{\text{work}}\,{\text{be}} \cr & 7x\,{\text{and}}\,4x\,{\text{respectively}} \cr & {\text{Then}},\,7x + 4x = \frac{1}{7} \cr & 11x = \frac{1}{7} \cr & x = \frac{1}{{77}} \cr & {\text{A’s}}\,{\text{1}}\,{\text{day’s}}\,{\text{work}} \cr & = {\frac{1}{{77}} \times {\text{7}}} = \frac{1}{{11}} \cr} $$
So, A will do the work in 11 days

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