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What will be the output of the following C# code?
static void main(string[] args)
{
int []arr = new int[]{ 1, 2, 3, 4, 5};
fun (ref arr);
for (int i = 0; i < arr.Length ; i++)
Console.WriteLine( arr[i] + ” “);
}
static void fun(ref int[]a)
{
a = new int[6];
a[3] = 32;
a[1] = 24;
}

What will be the output of the following C# code?
static void main(string[] args)
{
int []arr = new int[]{ 1, 2, 3, 4, 5};
fun (ref arr);
for (int i = 0; i < arr.Length ; i++)
Console.WriteLine( arr[i] + ” “);
}
static void fun(ref int[]a)
{
a = new int[6];
a[3] = 32;
a[1] = 24;
}
a) 0, 0, 32, 0, 0, 0
b) 0, 24, 0, 32, 0, 0
c) 24, 0, 32, 0, 0, 0
d) 0, 0, 32, 0, 0, 0

Answer: b
Explanation: index positions which are assigned the new values are passed as a reference parameter and hence rest positions are filled with zero values.
Output :
0 24 0 32 0 0

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