What will be the output of the following C# code?
static void Main(string[] args)
{
int i, j;
int[, ] arr = new int[ 3, 3];
for (i = 0; i < 3; ++i)
{
for (j = 0; j < 3; ++j)
{
arr[i, j] = i * 2 + i * 2;
Console.WriteLine(arr[i, j]);
}
Console.ReadLine();
}
}
a) 0, 0, 0 4, 4, 4 8, 8, 8
b) 4, 4, 4 8, 8, 8 12, 12, 12
c) 8, 8, 8 12, 12, 12 16, 16, 16
d) 0, 0, 0 1, 1, 1 2, 2, 2

Answer: a
Explanation: Since, with each value of of ‘i’ the value of ‘j’ is executed three times i.e
for i = 0, j = 0, 0, 0, i = 1, j = 2, 2, 2.
Output:
0, 0, 0 4, 4, 4 8, 8, 8