Consider the stack
| 5 |
| 4 |
| 3 |
| 2 |.
At this point, ‘*’ is encountered. What has to be done?
a) 5*4=20 is pushed into the stack
b) * is pushed into the stack
c) 2*3=6 is pushed into the stack
d) * is ignored
Answer: a
Explanation: When an operator is encountered, the first two operands of the stack are popped, evaluated and the result is pushed into the stack.
Related Posts
What is the output of the given code?
counter=1
if counter<=5
puts (counter)
counter=counter+1What is the output of the given code?
if(a==10 && b=9)
print “true”
else
print “false”
endWhich of the following are used for comparison?
What is the output of the given code?
a=10
b=9
if(a>b)
print (“a greater than b”)
else
print “Not greater”
endAssignment operator is also known as relational operator.
What is the output of the given code?
a=”string”
b=”strings”
if(a==b)
print (“a and b are same”)
else
print “Not same”
endWhat is the output of the given code?
test_1 = 17 > 16
puts(test_1)
test_2 = 21 <= 30
puts(test_2)
test_3 = 9 >= 9
puts(test_3)
test_4 = -11 > 4
puts(test_4)
Join The Discussion