a) Complexity of Insertion and Deletion at known position is O(n) in SLL and O(1) in DLL
b) SLL uses lesser memory per node than DLL
c) DLL has more searching power than SLL
d) Number of node fields in SLL is more than DLL
Answer: d
Explanation: To insert and delete at known positions requires complete traversal of the list in worst case in SLL, SLL consists of an item and a node field, while DLL has an item and two node fields, hence SLL occupies lesser memory, DLL can be traversed both ways(left and right), while SLL can traverse in only one direction, hence more searching power of DLL. Node fields in SLL is 2 (data and address of next node) whereas in DLL is 3(data, address to next node, address to previous node).
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counter=1
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if(a==10 && b=9)
print “true”
else
print “false”
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What is the output of the given code?
a=10
b=9
if(a>b)
print (“a greater than b”)
else
print “Not greater”
endAssignment operator is also known as relational operator.
What is the output of the given code?
a=”string”
b=”strings”
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print (“a and b are same”)
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print “Not same”
endWhat is the output of the given code?
test_1 = 17 > 16
puts(test_1)
test_2 = 21 <= 30
puts(test_2)
test_3 = 9 >= 9
puts(test_3)
test_4 = -11 > 4
puts(test_4)
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