What will be the output of the following Python code?
names1 = [‘Amir’, ‘Bear’, ‘Charlton’, ‘Daman’]
names2 = names1
names3 = names1[:]
names2[0] = ‘Alice’
names3[1] = ‘Bob’
sum = 0
for ls in (names1, names2, names3):
if ls[0] == ‘Alice’:
sum += 1
if ls[1] == ‘Bob’:
sum += 10
print sum
a) 11
b) 12
c) 21
d) 22

Answer: b
Explanation: When assigning names1 to names2, we create a second reference to the same list. Changes to names2 affect names1. When assigning the slice of all elements in names1 to names3, we are creating a full copy of names1 which can be modified independently.