What will be the output of the following C++ code?#include <iostream>using namespace std;void square (int *x){*x = (*x + 1) * (*x);}int main ( ){int num = 10;square(&num);cout << num;return 0;}

Register Now

Lost Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

What will be the output of the following C++ code?
#include <iostream>
using namespace std;
void square (int x)
{
x = (x + 1) (*x);
}
int main ( )
{
int num = 10;
square(&num);
cout << num;
return 0;
}

What will be the output of the following C++ code?
#include <iostream>
using namespace std;
void square (int *x)
{
*x = (*x + 1) * (*x);
}
int main ( )
{
int num = 10;
square(&num);
cout << num;
return 0;
}
a) 100
b) compile time error
c) 144
d) 110

Answer: d
Explanation: We have increased the x value in operand as x+1, so it will return as 110.
Output:
110

Register Now

Login

Lost Password

What will be the output of the following C++ code?#include <iostream>using namespace std;void square (int *x){*x = (*x + 1) * (*x);}int main ( ){int num = 10;square(&num);cout << num;return 0;}

Related Posts

Join The Discussion

What will be the output of the following C++ code?
#include <iostream>
using namespace std;
void square (int x)
{
x = (x + 1) (*x);
}
int main ( )
{
int num = 10;
square(&num);
cout << num;
return 0;
}