What will be the output of the following C++ code?#include <iostream>using namespace std;long factorial (long a){if (a > 1)return (a * factorial (a + 1));elsereturn (1);}int main (){long num = 3;cout << num << "! = " << factorial ( num );return 0;}

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What will be the output of the following C++ code?
#include <iostream>
using namespace std;
long factorial (long a)
{
if (a > 1)
return (a * factorial (a + 1));
else
return (1);
}
int main ()
{
long num = 3;
cout << num << “! = ” << factorial ( num );
return 0;
}

What will be the output of the following C++ code?
#include <iostream>
using namespace std;
long factorial (long a)
{
if (a > 1)
return (a * factorial (a + 1));
else
return (1);
}
int main ()
{
long num = 3;
cout << num << "! = " << factorial ( num );
return 0;
}
a) 6
b) 24
c) segmentation fault
d) compile time error

Answer: c
Explanation: As we have given in the function as a+1, it will exceed the size and so it arises the segmentation fault.
Output:
segmentation fault

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What will be the output of the following C++ code?#include <iostream>using namespace std;long factorial (long a){if (a > 1)return (a * factorial (a + 1));elsereturn (1);}int main (){long num = 3;cout << num << “! = ” << factorial ( num );return 0;}

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What will be the output of the following C++ code?
#include <iostream>
using namespace std;
long factorial (long a)
{
if (a > 1)
return (a * factorial (a + 1));
else
return (1);
}
int main ()
{
long num = 3;
cout << num << “! = ” << factorial ( num );
return 0;
}