What will be the output of the following C++ code?#include <iostream>using namespace std;void copy (int& a, int& b, int& c){a *= 2;b *= 2;c *= 2;}int main (){int x = 1, y = 3, z = 7;copy (x, y, z);cout << "x =" << x << ", y =" << y << ", z =" << z;return 0;}

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What will be the output of the following C++ code?
#include <iostream>
using namespace std;
void copy (int& a, int& b, int& c)
{
a = 2;
b = 2;
c *= 2;
}
int main ()
{
int x = 1, y = 3, z = 7;
copy (x, y, z);
cout << “x =” << x << “, y =” << y << “, z =” << z;
return 0;
}

What will be the output of the following C++ code?
#include <iostream>
using namespace std;
void copy (int& a, int& b, int& c)
{
a *= 2;
b *= 2;
c *= 2;
}
int main ()
{
int x = 1, y = 3, z = 7;
copy (x, y, z);
cout << "x =" << x << ", y =" << y << ", z =" << z;
return 0;
}
a) 2 5 10
b) 2 4 5
c) 2 6 14
d) 2 4 9

Answer: c
Explanation: Because we multiplied the values by 2 in the copy function.
Output:
x = 2,y = 6,z = 14

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What will be the output of the following C++ code?#include <iostream>using namespace std;void copy (int& a, int& b, int& c){a *= 2;b *= 2;c *= 2;}int main (){int x = 1, y = 3, z = 7;copy (x, y, z);cout << “x =” << x << “, y =” << y << “, z =” << z;return 0;}

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What will be the output of the following C++ code?
#include <iostream>
using namespace std;
void copy (int& a, int& b, int& c)
{
a = 2;
b = 2;
c *= 2;
}
int main ()
{
int x = 1, y = 3, z = 7;
copy (x, y, z);
cout << “x =” << x << “, y =” << y << “, z =” << z;
return 0;
}