What will be the output of the following C++ code?#include <iostream>#include <string>#include <cstdlib>using namespace std;void func(const int &a){int temp = 10;a = temp;cout<< a;}int main(int argc, char const *argv[]){int a = 5;func(a);return 0;}

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What will be the output of the following C++ code?
#include <iostream>
#include <string>
#include <cstdlib>
using namespace std;
void func(const int &a)
{
int temp = 10;
a = temp;
cout<< a;
}
int main(int argc, char const *argv[])
{
int a = 5;
func(a);
return 0;
}

What will be the output of the following C++ code?
#include <iostream>
#include <string>
#include <cstdlib>
using namespace std;
void func(const int &a)
{
int temp = 10;
a = temp;
cout<< a;
}
int main(int argc, char const *argv[])
{
int a = 5;
func(a);
return 0;
}
a) 5
b) 10
c) error
d) Segmentation fault

Answer: c
Explanation: As we are passing a as const reference to function therefore its value cannot be changes inside the function. So the program gives error.

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What will be the output of the following C++ code?#include <iostream>#include <string>#include <cstdlib>using namespace std;void func(const int &a){int temp = 10;a = temp;cout<< a;}int main(int argc, char const *argv[]){int a = 5;func(a);return 0;}

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What will be the output of the following C++ code?
#include <iostream>
#include <string>
#include <cstdlib>
using namespace std;
void func(const int &a)
{
int temp = 10;
a = temp;
cout<< a;
}
int main(int argc, char const *argv[])
{
int a = 5;
func(a);
return 0;
}