a) array[0];
b) array[1];
c) array(2);
d) array;
Answer: d
Explanation: To get the address of ith index of an array, we use following syntax (arr + i). So as we need address of first index we will use (arr + 0) equivalent to arr.
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What will be the output of the following C++ code?
#include <iostream>
using namespace std;
int main()
{
int a = 5, c;
void *p = & a;
double b = 3.14;
p = & b;
c = a + b;
cout << c << ‘\n’ << p;
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}What will be the output of the following C++ code?
#include <iostream>
using namespace std;
int main()
{
int n = 5;
void *p = & n;
int *pi = static_cast< int*>(p);
cout << *pi << endl; return 0; }
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