What will be the output of the following C++ code?#include <iostream>int main(){const int x;x = 10;printf("%d", x);return 0;}

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What will be the output of the following C++ code?
#include <iostream>
int main()
{
const int x;
x = 10;
printf(“%d”, x);
return 0;
}

What will be the output of the following C++ code?
#include <iostream>
int main()
{
const int x;
x = 10;
printf(“%d”, x);
return 0;
}
a) 10
b) Garbage value
c) Error
d) Segmentation fault

Answer: c
Explanation: In C++, all the constant variables must be initialized while declaration and they cannot be modified later in the program. Now in this program as we have declared the constant variable x in first line and initializing it in the next line therefore the program gives the error.

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What will be the output of the following C++ code?#include <iostream>int main(){const int x;x = 10;printf(“%d”, x);return 0;}

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What will be the output of the following C++ code?
#include <iostream>
int main()
{
const int x;
x = 10;
printf(“%d”, x);
return 0;
}