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What will be the output of the following C code?
#include <stdio.h>
int main()
{
int x = 2, y = 0;
int z = (y++) ? 2 : y == 1 && x;
printf(“%d\n”, z);
return 0;
}

What will be the output of the following C code?
#include <stdio.h>
int main()
{
int x = 2, y = 0;
int z = (y++) ? 2 : y == 1 && x;
printf(“%d\n”, z);
return 0;
}
a) 0
b) 1
c) 2
d) Undefined behaviour

Answer: b

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