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What will be the output of the following C code?
#include <stdio.h>
int main()
{
int y = 0;
if (1 |(y = 1))
printf(“y is %d\n”, y);
else
printf(“%d\n”, y);
}

What will be the output of the following C code?
#include <stdio.h>
int main()
{
int y = 0;
if (1 |(y = 1))
printf(“y is %d\n”, y);
else
printf(“%d\n”, y);
}
a) y is 1
b) 1
c) run time error
d) undefined

Answer: a

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