a) 54 year
b) 72 years
c) 105 years
d) 108 years
Answer: d
Explanation: Let the son’s age 18 years ago be x years,
Then man’s age 18 years ago = 3x years
$$\eqalign{
& \left( {3x + 18} \right) = 2\left( {x + 18} \right) \cr
& 3x + 18 = 2x + 36 \cr
& x = 18 \cr} $$
Sum of their present ages
$$\eqalign{
& \left( {3x + 18 + x + 18} \right){\text{years}} \cr
& \left( {4x + 36} \right){\text{years}} \cr
& \left( {4 \times 18 + 36} \right){\text{years}} \cr
& {\text{ 108 years}} \cr} $$
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