1. On 8th Dec, 2007 Saturday falls. What day of the week was it on 8th Dec, 2006?
a) Thursday
b) Sunday
c) Tuesday
d) Friday
Discussion
Explanation:
The year 2006 is an ordinary year. So, it has 1 odd day.
So, the day on 8th Dec, 2007 will be 1 day beyond the day on 8th Dec, 2006.
But, 8th Dec, 2007 is Saturday.
∴ 8th Dec, 2006 is Friday.
2. It was Thursday on 12th January 2006. What day of the week it will be on January 12th 2007 ?
a) Thursday
b) Saturday
c) Friday
d) Wednesday
Discussion
Explanation:
There is exactly 1 year, (365 days) between two dates.
2006 is an ordinary year. It has one odd day.
The day of the week on January 12th 2007 is one day beyond Thursday ⇒ Friday
3. If 1st October is Sunday, then 1st November will be
a) Thursday
b) Wednesday
c) Monday
d) Tuesday
Discussion
Explanation:
Given that 1st October is Sunday
Number of days in October = 31
31 days = 3 odd days
(As we can reduce multiples of 7 from odd days which will not change anything)
Hence 1st November = (Sunday + 3 odd days) = Wednesday
4. What day of the week was 20th June 1837?
a) Wednesday
b) Tuesday
c) Monday
d) Thursday
Discussion
Explanation:
20th June, 1837 means 1836 complete years + first 5 months of the year 1837 + 20 days of June
1600 years give no odd days
200 years give 3 odd days
36 years give (36 + 9 ) or 3 odd days
Thus 1836 years give 6 odd days
From 1st January to 20th June there are 3 odd days
Odd days: January 3, February 0, March 3, April 2, May 3, June 6 = 17
Thus the total number of odd days = 6 + 3 or 2 odd days
This means that the 20th of June fell on 2nd day commencing from Monday.
The required day was Tuesday.
5. If today is Monday, what will be the day 350 days from now?
a) Monday
b) Thursday
c) Tuesday
d) Wednesday
Discussion
Explanation:
350 days, $$\frac{{350}}{7}$$ = 50, no odd days, so it will be a Monday.
6. What was the day on 25th January, 1975?
a) Friday
b) Sunday
c) Saturday
d) Monday
Discussion
Explanation:
Counting the years 1600 + 300 + 74
In 1600 years, there are zero odd days
In 300 years, there is one odd day
In 74 years, there are 18 leap years and 56 normal years, so the odd days are:
18(2) + 56(1) = 36 + 56 = 92,
Which is 13 weeks and 1 odd day
In 25 days of January, 1975, there are 3 weeks and 4 odd days
Total odd days = 0 + 1 + 1 + 4
six odd days, so it was a Saturday.
7. January 1, 2008 is Tuesday. What day of the week lies on Jan 1, 2009?
a) Sunday
b) Wednesday
c) Monday
d) Thursday
Discussion
Explanation:
The year 2008 is a leap year. So, it has 2 odd days.
1st day of the year 2008 is Tuesday (Given)
So, 1st day of the year 2009 is 2 days beyond Tuesday.
Hence, it will be Thursday.
8. On 2007, What was the date of last Saturday in May month?
a) 24th May
b) 28th May
c) 26th May
d) 22th May
Discussion
Explanation:
1 - May - 2007
$$\eqalign{ & = \frac{{1 + 2 + 7 + 1 + 6}}{7} \cr & = \frac{{17}}{7} \cr & = 3 \cr & = {\text{Tuesday}} \cr} $$
= May 1st → Tuesday + 5 days = Saturday = 5th may
5th may + 7 days = Saturday = 12th may
12th may + 7 days = Saturday = 19th may
19th may + 7 days = Saturday = 26th may
= Answer = 26th may
9. What was the day of the week on 10th March 1996?
a) Friday
b) Saturday
c) Thursday
d) Sunday
Discussion
Explanation:
$$\eqalign{ & \frac{{10 + 4 + 96 + 24 + 0}}{7} \cr & = \frac{{134}}{7} \cr & = 1 \cr & = {\text{Sunday}} \cr} $$
10. What day of the week will 22 Apr 2222 be?
a) Monday
b) Wednesday
c) Tuesday
d) Thursday
Discussion
Explanation:
22 Apr 2222 = (2221 years + period from 1-Jan-2222 to 22-Apr-2222)
We know that number of odd days in 400 years = 0
Hence the number of odd days in 2000 years = 0 (Since 2000 is a perfect multiple of 400)
Number of odd days in the period 2001-2200
= Number of odd days in 200 years
= 5 x 2 = 10 = 3
(As we can reduce perfect multiples of 7 from odd days without affecting anything)
Number of odd days in the period 2201-2221
= 16 normal years + 5 leap years
= 16 x 1 + 5 x 2 = 16 + 10 = 26 = 5 odd days
Number of days from 1-Jan-2222 to 22 Apr 2222
= 31 (Jan) + 28 (Feb) + 31 (Mar) + 22(Apr) = 112
112 days = 0 odd day
Total number of odd days = (0 + 3 + 5 + 0) = 8 = 1 odd day
1 odd days = Monday
Hence 22 Apr 2222 is Monday
11. Arun went for a movie nine days ago. He goes to watch movies only on Thursdays. What day of the week is today?
a) Friday
b) Thursday
c) Wednesday
d) Saturday
Discussion
Explanation:
Clearly it can be understood from the question that 9 days ago was a Thursday
Number of odd days in 9 days = 2 (As 9 - 7 = 2, reduced perfect multiple of 7 from total days)
Hence today = (Thursday + 2 odd days) = Saturday
12. January 1, 2007 was Monday. What day of the week lies on Jan. 1, 2008?
a) Sunday
b) Tuesday
c) Monday
d) Wednesday
Discussion
Explanation:
The year 2007 is an ordinary year. So, it has 1 odd day.
1st day of the year 2007 was Monday.
1st day of the year 2008 will be 1 day beyond Monday.
Hence, it will be Tuesday.
13. What was the day of the week on 24th July 2011?
a) Sunday
b) Wednesday
c) Monday
d) Tuesday
Discussion
Explanation:
Formula : (Date + Month code + No.of years + No.of leap year + Century code)/7
$$\eqalign{ & = \frac{{24 + 0 + 11 + 2 + 6}}{7} \cr & = \frac{{43}}{7} \cr & = 1 \cr & = {\text{Sunday}} \cr} $$
14. How many days will there be from 26th January, 1996 to 15th May, 1996 (both days included)?
a) 113
b) 111
c) 110
d) 112
Discussion
Explanation:
Number of days from 26-Jan-1996 to 15-May-1996 (both days included)
= 6(Jan) + 29(Feb) + 31 (Mar) + 30(Apr)+ 15(May)
= 111
15. On 8th Feb, 2005 it was Tuesday. What was the day of the week on 8th Feb, 2004?
a) Monday
b) Sunday
c) Tuesday
d) Wednesday
Discussion
Explanation:
The year 2004 is a leap year. It has 2 odd days.
∴ The day on 8th Feb, 2004 is 2 days before the day on 8th Feb, 2005.
Hence, this day is Sunday.
16. Today is 3rd November. The day of the week is Monday. This is a leap year. What will be the day of the week on this date after 3 years?
a) Thursday
b) Wednesday
c) Tuesday
d) Monday
Discussion
Explanation:
This is a leap year. So, none of the next 3 years will be leap years. Each year will give one odd day so the day of the week will be 3 odd days beyond Monday i.e. it will be Thursday.
17. If the first day of a year (other than leap year) was Friday, then which was the last day of that year?
a) Saturday
b) Thursday
c) Wednesday
d) Friday
Discussion
Explanation:
Given that first day of a normal year was Friday
Odd days of the mentioned year = 1 (Since it is an ordinary year)
Hence First day of the next year = (Friday + 1 Odd day) = Saturday
Therefore, last day of the mentioned year = Friday
18. Which of the following is not a leap year?
a) 1200
b) 700
c) 2000
d) 800
Discussion
Explanation:
The century divisible by 400 is a leap year.
∴ The year 700 is not a leap year.
19. If the seventh day of a month is three days earlier than Friday, What day will it be on the nineteenth day of the month?
a) Tuesday
b) Monday
c) Wednesday
d) Sunday
Discussion
Explanation:
Given that seventh day of a month is three days earlier than Friday
⇒ Seventh day is Tuesday
⇒ 14th is Tuesday
⇒ 19th is Sunday
20. Today is Thursday. What will be the day of the week after 94 days?
a) Sunday
b) Wednesday
c) Tuesday
d) Monday
Discussion
Explanation:
94 days = (13 × 7) + 3 = 3 odd days.
The required day is 3 days beyond Thursday i.e., Sunday
21. The year next to 2003 will have the same calendar as that of the year 2003?
a) 2024
b) 2014
c) 2009
d) 2020
Discussion
Explanation: Given year 2003, when divided by 4 leaves a remainder of 3.
Note: When remainder is 3, 11 is added to the given year to get the result.
2003 + 11 = 2014
22. On 19th June, 1984 Monday falls. What day of the week was it on 19th June, 1985?
a) Sunday
b) Monday
c) Tuesday
d) Wednesday
Discussion
Explanation: The year 1985 is an ordinary year. So, it has 1 odd day.
So, the day on 19th June, 1985 will be 1 day after the day on 19th June, 1984.
But, 19th June,1984 is Monday
So, 19th June, 1985 is Tuesday.
23. Suppose today is Friday, what day of the week will it be 65 days from now?
a) Saturday
b) Sunday
c) Friday
d) Thursday
Discussion
Explanation: The day of the week repeats every 7 days.
Given today is Friday. Again Friday is repeated on the 7th day, 14th,.... on 7 multiple days.
Hence, Friday is on the 63rd day, as 63 is multiple of 7.
The required day of the week on the 65th day is Sunday.
24. How many seconds in 10 years?
a) 31523500 sec
b) 315360000 sec
c) 315423000 sec
d) 315354000 sec
Discussion
Explanation: 1 year = 365 days
1 day = 24 hours
1 hour = 60 minutes
1 minute = 60 seconds
Then, 1 year = 365 x 24 x 60 x 60 seconds = 8760 x 3600
1 year = 31536000 seconds
10 years = 31536000 x 10 = 315360000 seconds
25. The calendar of year 1939 is same as which year?
a) 1943
b) 1964
c) 1950
d) 1956
Discussion
Explanation: Given year 1939, when divided by 4 leaves a remainder of 3
Note: When remainder is 3, 11 is added to the given year to get the result
So, 1939 + 11 = 1950
26. What is two weeks from today?
a) Same day
b) Previous day
c) Next day
d) none
Discussion
Explanation: We know that the day repeats every 7 days, 14 days, 21 days, .........
So if today is Monday, after 7 days it is again Monday, after 14 days again it is Monday.
Hence, after 2 weeks i.e, 14 days the day repeats and is the same day.
27. How old are you if you are born in 1995?
a) 22
b) 23
c) 24
d) 25
Discussion
Explanation: Calculating Age has 2 conditions. Let your Birthday is on January 1st.
1. If the month in which you are born is completed in the present year i.e, your birthday, then
Your Age = Present year - Year you are born
As of now, Let present year = 2018
Age = 2018 - 1995 = 23 years.
2. If the month in which you are born is not completed in the present year i.e, your birthday, then
Your Age = Last year - Year you are born
As of now, Let present year = 2018
Age = 2017 - 1995 = 22 years.
28. What was the day on 2nd Jan 1901 ?
a) Tuesday
b) Wednesday
c) Monday
d) Thursday
Discussion
Explanation: 2nd Jan 1901 means
(1900 years and 2 day)
Now, 1600 years have 0 odd day
300 years have 1 odd day
2 days has 2 odd day
Total no. of odd days = 0 + 1 + 2 = 3 days
The day on 2nd Jan 1901 was Wednesday.
29. What was the day on 16th June,1993?
a) Saturday
b) Monday
c) Wednesday
d) Friday
Discussion
Explanation: 16 June, 1993 = (1992 years + Period from 1.1.1993 to 16.6.1993)
Odd days in 1600 years = 0
Odd days in 300 years = 1
92 years = (69 ordinary years + 23 leap year) = (69 x 1 + 23 x 2)= 3 odd days
Jan. Feb. March April May June
(31 + 28 + 31 + 30 + 31 + 16 ) = 167 days
167 days = (23 weeks + 6 days) =6 odd days.
Total number of odd days = (0 + 1 + 3 + 6) = 3 odd days.
Given day is Wednesday.
30. Which century year is a leap year?
a) 1900
b) 1700
c) 1600
d) 1100
Discussion
Explanation: For an century year,it is divided by 400,when leaves a remainder 0 then it is a leap year. So, 1600
31. Which two months in a year have the same calendar?
a) October, December
b) April, November
c) June, October
d) April, July
Discussion
Explanation: If the period between the two months is divisible by 7, then that two months will have the same calendar.
(a) Oct + Nov = 31 + 30 = 61 (not divisible by 7)
(b) Apr + May + Jun + Jul + Aug + Sep + Oct = 30 + 31 + 30 + 31 + 31 + 30 + 31 = 214 (not divisible by 7)
(c) Jun + July + Aug + Sep = 30 + 31 + 31 + 30 = 122 (not divisible by 7)
(d) Apr + May + June = 30 + 31 + 30 = 91 (divisible by 7)
Hence, April and July months will have the same calendar.
32. How many leap years do 300 years have?
a) 75
b) 74
c) 72
d) 73
Discussion
Explanation: Given year is divided by 4, and the quotient gives the number of leap years.
Here, 300 ÷ 4 = 75
But, as 100, 200 and 300 are not leap years ⇒ 75 - 3 = 72 leap years.
33. On what dates of July. 2004 did Monday fall?
a) 6th, 10th, 21th, 30th
b) 12th, 7th, 19th, 28th
c) 5th, 10th, 24th, 17th
d) 5th, 12th, 19th, 26th
Discussion
Explanation: Let us find the day on 1st July, 2004.
2000 years have 0 odd day. 3 ordinary years have 3 odd days.
Jan. Feb. March April May June July
31 + 29 + 31 + 30 + 31 + 30 + 1
= 183 days
= (26 weeks + 1 day)
Total number of odd days = (0 + 3 + 1) odd days = 4 odd days.
1st July 2004 was 'Thursday'
Thus, 1st Monday in July 2004 as on 5th July. Hence, during July 2004, Monday fell on 5th, 12th, 19th and 26th.
34. The year next to 2005 will have the same calendar as that of the year 2005?
a) 2016
b) 2022
c) 2011
d) None
Discussion
Explanation: Repetition of leap year ⇒ Add + 28 to the Given Year.
Repetition of non leap year
Step 1 : Add + 11 to the Given Year. If Result is a leap year, Go to step 2.
Step 2: Add + 6 to the Given Year.
Given Year is 2005, Which is a non leap year.
Step 1 : Add + 11 to the given year (i.e 2005 + 11) = 2016, Which is a leap year.
Step 2 : Add + 6 to the given year (i.e 2005 + 6) = 2011
Therefore, The calendar for the year 2005 will be same for the year 2011
35. If Feb 12th,1986 falls on Wednesday then Jan 1st,1987 falls on which day?
a) Wednesday
b) Tuesday
c) Thursday
d) Friday
Discussion
Explanation: First,we count the number of odd days for the left over days in the given period.
Here,given period is 12.2.1986 to 1.1.1987
Feb Mar Apr May June July Aug Sept Oct Nov Dec Jan
16 31 30 31 30 31 31 30 31 30 31 1 (left days)
2 + 3 + 2 + 3 + 2 + 3 + 3 + 2 + 3 + 2 + 3 + 1(odd days)
= 1 odd day
So, given day Wednesday + 1 = Thursday is the required result.
36. What was the day of the week on 16th August, 1947?
a) Sunday
b) Monday
c) Saturday
d) Thursday
Discussion
Explanation: 15th August, 1947 = (1946 years + Period from 1st Jan., 1947 to 15th )
Counting of odd days:
1600 years have 0 odd day. 300 years have 1 odd day.
47 years = (11 leap years + 36 ordinary years)
= [(11 x 2) + (36 x 1) ] odd days
= 58 odd days
= 2 odd days
Jan Feb Mar Apr May Jun Jul Aug
= 31 + 28 + 31 + 30 + 31 + 30 + 31 + 15
= 227 days
= (32 weeks + 3 days)
= 3
Total number of odd days
= (0 + 1 + 2 + 3) odd days
= 6 odd days
Hence, the required day was 'Saturday'.
37. Prove that any date in March of a year is the same day of the week corresponding date in November that year.
a) Same day
b) Not same day
c) Next day
d) Previous day
Discussion
Explanation: We will show that the number of odd days between last day of February and last day of October is zero.
March April May June July Aug. Sept. Oct.
31 + 30 + 31 + 30 + 31 + 31 + 30 + 31
= 241 days
= 35 weeks
= 0 odd day
Number of odd days during this period = 0.
Thus, 1st March of an year will be the same day as 1st November of that year. Hence, the result follows.
38. If today is Saturday, what will be the day 350 days from now ?
a) Saturday
b) Friday
c) Sunday
d) Monday
Discussion
Explanation: 350 days = $$\frac{{350}}{7}$$ = 50 weeks, i.e No odd days,
So it will be a Saturday.
39. The calendar for the year 1988 is same as which upcoming year ?
a) 2012
b) 2014
c) 2016
d) 2010
Discussion
Explanation: We already know that the calendar after a leap year repeats again after 28 years.
Here 1988 is a Leap year, then the same calendar will be in the year = 1988 + 28 = 2016.
40. Given that on 9th August 2016 is Saturday. What was the day on 9th August 1616 ?
a) Saturday
b) Sunday
c) Friday
d) Monday
Discussion
Explanation: We know that, After every 400 years, the same day occurs.
If 9th August 2016 is Saturday, before 400 years
i.e., on 9th August 1616 has to be Saturday.
41. It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010?
a) Sunday
b) Saturday
c) Friday
d) Wednesday
Discussion
Explanation: On 31st December, 2005 it was Saturday.
Number of odd days from the year 2006 to the year 2009 = (1 + 1 + 2 + 1) = 5 days.
On 31st December 2009, it was Thursday.
On 1st Jan, 2010 it is Friday.
42. What was the day of the week on 28th May, 2006?
a) Thursday
b) Friday
c) Saturday
d) Sunday
Discussion
Explanation: 28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)
Odd days in 1600 years = 0
Odd days in 400 years = 0
5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) ≡ 6 odd days
Jan. Feb. March April May
(31 + 28 + 31 + 30 + 28 ) = 148 days
148 days = (21 weeks + 1 day) ≡ 1 odd day.
Total number of odd days = (0 + 0 + 6 + 1) = 7 ≡ 0 odd day.
Given day is Sunday.
43. What was the day of the week on 17th June, 1998?
a) Monday
b) Tuesday
c) Wednesday
d) Thursday
Discussion
Explanation: 17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)
Odd days in 1600 years = 0
Odd days in 300 years = (5 x 3) ≡ 1
97 years has 24 leap years + 73 ordinary years.
Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days.
Jan. Feb. March April May June
(31 + 28 + 31 + 30 + 31 + 17) = 168 days
168 days = 24 weeks = 0 odd day.
Total number of odd days = (0 + 1 + 2 + 0) = 3.
Given day is Wednesday.
44. What will be the day of the week 15th August, 2010?
a) Sunday
b) Monday
c) Tuesday
d) Friday
Discussion
Explanation: 15th August, 2010 = (2009 years + Period 1.1.2010 to 15.8.2010)
Odd days in 1600 years = 0
Odd days in 400 years = 0
9 years = (2 leap years + 7 ordinary years) = (2 x 2 + 7 x 1) = 11 odd days ≡ 4 odd days.
Jan. Feb. March April Mayb June July Aug.
(31 + 28 + 31 + 30 + 31 + 30 + 31 + 15) = 227 days
227 days = (32 weeks + 3 days) ≡ 3 odd days.
Total number of odd days = (0 + 0 + 4 + 3) = 7 ≡ 0 odd days.
Given day is Sunday.
45. Today is Monday. After 61 days, it will be:
a) Wednesday
b) Saturday
c) Tuesday
d) Thursday
Discussion
Explanation: Each day of the week is repeated after 7 days.
After 63 days, it will be Monday.
After 61 days, it will be Saturday.
46. What was the day of the week on 26-January-1950?
a) Monday
b) Sunday
c) Thursday
d) Wednesday
Discussion
Explanation: Formula : (Date + Month code + No.of years + No.of leap year + Century code)/7
$$\eqalign{ & = \frac{{26 + 1 + 50 + 12 + 0}}{7} = \frac{{89}}{7} \cr & = 5 \cr & = {\text{Thursday}} \cr} $$
47. Today is Thursday. What day of the week it was 30 days?.
a) Sunday
b) Monday
c) Tuesday
d) Wednesday
Discussion
Explanation: 30 days = 4 x 7 + 2 = 2 odd days
The day is 2 days before Thursday i.e Tuesday
48. 01-Jan-2007 was Monday. What day of the week lies on 01-Jan-2008?
a) Monday
b) Tuesday
c) Wednesday
d) Thursday
Discussion
Explanation: Given that January 1, 2007 was Monday.
Odd days in 2007 = 1 (we have taken the complete year 2007 because we need to find out the odd days from 01-Jan-2007 to 31-Dec-2007, that is the whole year 2007)
Hence January 1, 2008 = (Monday + 1 Odd day) = Tuesday
49. 1.12.91 is the first Sunday. Which is the fourth Tuesday of December 91?
a) 20.12.91
b) 22.12.91
c) 24.12.91
d) 25.12.91
Discussion
Explanation: Given that 1.12.91 is the first Sunday
Hence we can assume that 3.12.91 is the first Tuesday
If we add 7 days to 3.12.91, we will get second Tuesday
If we add 14 days to 3.12.91, we will get third Tuesday
If we add 21 days to 3.12.91, we will get fourth Tuesday
⇒ Fourth Tuesday = (3.12.91 + 21 days) = 24.12.91
50. Today is Thursday. The day after 59 days will be?
a) Sunday
b) Monday
c) Tuesday
d) Wednesday
Discussion
Explanation: 59 days = 8 weeks 3 days = 3 odd days
Hence if today is Thursday, After 59 days, it will be
= (Thursday + 3 odd days)
= Sunday
51. What was day of the week on 21-September-1987?
a) Saturday
b) Sunday
c) Monday
d) Tuesday
Discussion
Explanation: Formula : (Date + Month code + No.of years + No.of leap year + Century code)/7
$$\eqalign{ & = \frac{{21 + 6 + 87 + 21 + 0}}{7} = \frac{{135}}{7} \cr & = 2 \cr & = {\text{Monday}} \cr} $$
52. How many odd days are there from 13th May, 2005 to 19th August 2005 (both inclusive)?
a) 1
b) 2
c) 3
d) 4
Discussion
Explanation: Here we have to count the number days from 13th May, 2005 to 18rd August 2005 ( both inclusive)
From 13th to 31st May = 19 days
In June = 30 days
In July = 31 days
From 1st to 19th April = 19 days
Total number of days = 19 + 30 + 31 + 19 = 99 days
The number of odd days are = 14 x 7 + 1 = 99
So there is 1 odd day in the given period
53. What is the year next to 1990 which will have the same calendar as that of the year 1990?
a) 1992
b) 2001
c) 1995
d) 1996
Discussion
Explanation: For a year to have the same calendar with 1990 ,total odd days from 1990 should be 0. Take the year 1992 from the given choices.
Total odd days in the period 1990-1991 = 2 normal years
⇒ 2 x 1 = 2 odd daysTake the year 1995 from the given choices.
Number of odd days in the period 1990-1994 = 4 normal years + 1 leap year
⇒ 4 x 1 + 1 x 2 = 6 odd daysTake the year 1996 from the given choices.
Number of odd days in the period 1990-1995 = 5 normal years + 1 leap year
⇒ 5 x 1 + 1 x 2 = 7 odd days = 0 odd days
(As we can reduce multiples of 7 from odd days which will not change anything) Though number of odd days in the period 1990-1995 is 0, there is a catch here.
1990 is not a leap year whereas 1996 is a leap year.
Hence calendar for 1990 and 1996 will never be the same.Take the year 2001 from the given choices. Number of odd days in the period 1990-2000 = 8 normal years + 3 leap years
⇒ 8 x 1 + 3 x 2 = 14 odd days = 0 odd days
Also, both 1990 and 2001 are normal years.
Hence 1990 will have the same calendar as that of 2001
54. Find the number of odd days in 126 years.
a) 1
b) 2
c) 3
d) 4
Discussion
Explanation: A period of 100 years has 5 odd days . In 26 years , 4 are leap, remaining are ordinary years
125 years = 100 years + 26 years
= 100 years + 6 leap years + 20 ordinary years
= 5 odd days + 12 odd days + 20 odd days
= 37 odd days = 5 x 7 +2 = 2 odd days
55. If the day before yesterday was Thursday, when will Sunday be?
a) Today
b) Tomorrow
c) Two days after today
d) Day after tomorrow
Discussion
Explanation: Day before yesterday was Thursday
Yesterday was a Friday
Today is a Saturday
Tomorrow is a Sunday
56. Second & fourth Saturdays and every Sunday is a holiday. How many working days will be there in a month of 31 days beginning on a Friday ?
a) 24 days
b) 23 days
c) 22 days
d) 25 days
Discussion
Explanation: Given that the month begins on a Friday and has 31 days
Sundays = 3rd, 10th, 17th, 24th, 31st
⇒ Total Sundays = 5
Every second & fourth Saturday is holiday. 2nd & 4th Saturday in every month = 2
Total days in the month = 31
Total working days = 31 - (5 + 2) = 24 days.
57. On 17th March, 1997 Monday falls. What day of the week was it on 17th March, 1996?
a) Monday
b) Tuesday
c) Saturday
d) Sunday
Discussion
Explanation: The year 1996 is a leap year. So, it has 2 odd days. But 17th March comes after 29th February.
So, the day on 17th March, 1997 will be 1 day beyond the day on 17th March,1996.
Here 17th March, 1997 is Monday. So, 17th March, 1996 is Sunday.
58. Which year has 366 days?
a) 1900
b) 1200
c) 2500
d) 1700
Discussion
Explanation: When a century year leaves a remainder 0, when divided by 400 then it is a leap year (366 days).
So, 1200 has 366 days.
59. What is 90 days from today?
a) 18th April, Friday
b) 20th April, Saturday
c) 21th April, Sunday
d) 19th April, Saturday
Discussion
Explanation: Given Today is 20th January 2017, Sunday
In january, we have 31 days
February - 28 days (Non leap year)
March - 31 days
April - 30 days
⇒ Remaining days = 31 - 20 = 11 in Jan
11 in Jan + 28 in Feb + 31 in Mar = 11 + 28 + 31 = 70 days
More 20 days to complete 90 days ⇒ upto 20th April
Therefore, after 90 days from today i.e, 20th Jan 2017 is 20th Apr 2017.
Now, the day of the week will be
$$\frac{{90}}{7}$$ ⇒ Remainder '6'
As the day starts with '0' on sunday
6 ⇒ Saturday.
Required day is 20th April, Saturday.
60. On 24th Nov, 2007 Thursday falls. What day of the week was it on 10th Nov, 2006 ?
a) Wednesday
b) Tuesday
c) Friday
d) Thursday
Discussion
Explanation: The year 2006 is an ordinary year. So, it has 1 odd day.
So, the day on 24th Nov, 2007 will be 1 day beyond the day on 24
th Nov, 2006.
But, 24th Nov, 2007 is Thursday.
24 - 10 = 14 days.
Therefore, 2 weeks ago it is same day.
10th Nov, 2006 is one day before 10th Nov, 2007 i.e. it is Wednesday.
61. Second Saturday and every Sunday is a holiday. How many working days will be there in a month of 30 days beginning on a Saturday?
a) 21
b) 22
c) 23
d) 24
Discussion
Explanation: Mentioned month begins on a Saturday and has 30 days
Sundays = 2nd, 9th, 16th, 23rd, 30th
⇒ Total Sundays = 5
Every second Saturday is holiday.
1 second Saturday in every month
Total days in the month = 30
Total working days = 30 - (5 + 1) = 24
62. December 9, 2001 is Sunday. What was the day on December 9, 1971?
a) Monday
b) Tuesday
c) Wednesday
d) Thursday
Discussion
Explanation: Total number of days = 30 × 365 + 8 days from leap years = 10958
Number of weeks = 1565
December 9, 1971 must have been Tuesday.
63. What day of the week was 1st January 1901
a) Monday
b) Tuesday
c) Wednesday
d) Thursday
Discussion
Explanation: 1st Jan 1901 = (1900 years + 1st Jan 1901)
We know that number of odd days in 400 years = 0
Hence the number of odd days in 1600 years = 0 (Since 1600 is a perfect multiple of 400)
Number of odd days in the period 1601 - 1900
= Number of odd days in 300 years
= 5 x 3 = 15 = 1
(As we can reduce perfect multiples of 7 from odd days without affecting anything)
1st Jan 1901 = 1 odd day
Total number of odd days = (0 + 1 + 1) = 2
2 odd days = Tuesday
1 January 1901 is Tuesday.
64. Today is 5th August. The day of the week is Wednesday. This is a leap year. What will be the day of the week on this date after 3 years?
a) Wednesday
b) Thursday
c) Friday
d) Saturday
Discussion
Explanation: This is a leap year.
So, none of the next 3 years will be leap years.
Each ordinary year has one odd day, so there are 3 odd days in next 3 years.
The day of the week will be 3 odd days beyond Wednesday i.e. it will be Saturday
65. January 1, 2004 was a Thursday, what day of the week lies on January 1, 2005
a) Wednesday
b) Thursday
c) Friday
d) Saturday
Discussion
Explanation: Given that January 1, 2004 was Thursday.
Odd days in 2004 = 2 (because 2004 is a leap year)
(Also note that we have taken the complete year 2004 because we need to find out the odd days from 01-Jan-2004 to 31-Dec-2004, that is the whole year 2004)
January 1, 2005 = (Thursday + 2 odd days) = Saturday
66. How many days are there from 3rd February, 2012 to 18th April 2012 (both inclusive)?
a) 55 days
b) 65 days
c) 76 days
d) 85 days
Discussion
Explanation: Here we have to count the number days from 3rd February, 2012 to 18th April 2012 ( both inclusive)
The given year is leap year, So February month has 29 days
From 3rd to 29th February = 27 days
In March = 31 days
From 1st to 18th April = 18 days
Total number of days = 27 + 31 + 18 = 76 days
67. What was the day on 15th august 1947 ?
a) Friday
b) Saturday
c) Sunday
d) Thursday
Discussion
Explanation: 15th Aug, 1947 = (1946 years + Period from 1.1.1947 to 15.8.1947)
Odd days in 1600 years = 0
Odd days in 300 years = 1
46 years
= (35 ordinary years + 11 leap years)
= (35 x 1 + 11 x 2)
= 57 (8 weeks + 1 day)
= 1 odd day
Jan. Feb. Mar. Apr. May. Jun. Jul. Aug
( 31 + 28 + 31 + 30 + 31 + 30 + 31 + 15 )
= 227 days
= (32 weeks + 3 days)
= 3 odd days
Total number of odd days = (0 + 1 + 1 + 3) = 5 odd days
Hence, as the number of odd days = 5, given day is Friday.
68. What was the day of the week on, 16th July, 1776?
a) Tuesday
b) Wednesday
c) Monday
d) Saturday
Discussion
Explanation: 16th July, 1776 = (1775 years + Period from 1st Jan, 1776 to 16th July, 1776)
Counting of odd days :
1600 years have 0 odd day
100 years have 5 odd days
75 years = (18 leap years + 57 ordinary years)
= [(18 x 2) + (57 x 1)]
= 93 (13 weeks + 2 days)
= 2 odd days
1775 years have (0 + 5 + 2) odd days = 7 odd days = 0 odd day
Jan Feb Mar Apr May Jun Jul
31 + 29 + 31 + 30 + 31 + 30 + 16
= 198 days
= (28 weeks + 2 days)
Total number of odd days = (0 + 2) = 2
Required day was 'Tuesday'.
69. The maximum gap between two successive leap year is?
a) 4
b) 8
c) 2
d) 1
Discussion
Explanation: Ex: 1896 is a leap year.The next leap year comes in 1904 (1900 is not a leap year).
The length of the solar year, however, is slightly less than 365$$\frac{1}{4}$$ days-by about 11 minutes. To compensate for this discrepancy, the leap year is omitted three times every four hundred years.
In other words, a century year cannot be a leap year unless it is divisible by 400. Thus 1700, 1800, and 1900 were not leap years, but 1600, 2000, and 2400 are leap years.
70. How many leap years does 100 years have?
a) 25
b) 24
c) 4
d) 26
Discussion
Explanation: Given year is divided by 4, and the quotient gives the number of leap years.
Here, 100 ÷ 4 = 25
As 100 is not a leap year ⇒ 25 - 1 = 24 leap years.