1. On 8^{th} Dec, 2007 Saturday falls. What day of the week was it on 8^{th} Dec, 2006?

a) Thursday

b) Sunday

c) Tuesday

d) Friday

Explanation:

The year 2006 is an ordinary year. So, it has 1 odd day.

So, the day on 8

^{th}Dec, 2007 will be 1 day beyond the day on 8

^{th}Dec, 2006.

But, 8

^{th}Dec, 2007 is Saturday.

∴ 8

^{th}Dec, 2006 is Friday.

2. It was Thursday on 12^{th} January 2006. What day of the week it will be on January 12^{th} 2007 ?

a) Thursday

b) Saturday

c) Friday

d) Wednesday

Explanation:

There is exactly 1 year, (365 days) between two dates.

2006 is an ordinary year. It has one odd day.

The day of the week on January 12

^{th}2007 is one day beyond Thursday ⇒ Friday

3. If 1^{st} October is Sunday, then 1^{st} November will be

a) Thursday

b) Wednesday

c) Monday

d) Tuesday

Explanation:

Given that 1st October is Sunday

Number of days in October = 31

31 days = 3 odd days

(As we can reduce multiples of 7 from odd days which will not change anything)

Hence 1

^{st}November = (Sunday + 3 odd days) = Wednesday

4. What day of the week was 20^{th} June 1837?

a) Wednesday

b) Tuesday

c) Monday

d) Thursday

Explanation:

20

^{th}June, 1837 means 1836 complete years + first 5 months of the year 1837 + 20 days of June

1600 years give no odd days

200 years give 3 odd days

36 years give (36 + 9 ) or 3 odd days

Thus 1836 years give 6 odd days

From 1

^{st}January to 20

^{th}June there are 3 odd days

Odd days: January 3, February 0, March 3, April 2, May 3, June 6 = 17

Thus the total number of odd days = 6 + 3 or 2 odd days

This means that the 20th of June fell on 2nd day commencing from Monday.

The required day was Tuesday.

5. If today is Monday, what will be the day 350 days from now?

a) Monday

b) Thursday

c) Tuesday

d) Wednesday

Explanation:

350 days, $$\frac{{350}}{7}$$ = 50, no odd days, so it will be a Monday.

6. What was the day on 25^{th} January, 1975?

a) Friday

b) Sunday

c) Saturday

d) Monday

Explanation:

Counting the years 1600 + 300 + 74

In 1600 years, there are zero odd days

In 300 years, there is one odd day

In 74 years, there are 18 leap years and 56 normal years, so the odd days are:

18(2) + 56(1) = 36 + 56 = 92,

Which is 13 weeks and 1 odd day

In 25 days of January, 1975, there are 3 weeks and 4 odd days

Total odd days = 0 + 1 + 1 + 4

six odd days, so it was a Saturday.

7. January 1, 2008 is Tuesday. What day of the week lies on Jan 1, 2009?

a) Sunday

b) Wednesday

c) Monday

d) Thursday

Explanation:

The year 2008 is a leap year. So, it has 2 odd days.

1

^{st}day of the year 2008 is Tuesday (Given)

So, 1

^{st}day of the year 2009 is 2 days beyond Tuesday.

Hence, it will be Thursday.

8. On 2007, What was the date of last Saturday in May month?

a) 24^{th} May

b) 28^{th} May

c) 26^{th} May

d) 22^{th} May

Explanation:

1 - May - 2007

$$\eqalign{ & = \frac{{1 + 2 + 7 + 1 + 6}}{7} \cr & = \frac{{17}}{7} \cr & = 3 \cr & = {\text{Tuesday}} \cr} $$

= May 1

^{st}→ Tuesday + 5 days = Saturday = 5

^{th}may

5

^{th}may + 7 days = Saturday = 12

^{th}may

12

^{th}may + 7 days = Saturday = 19

^{th}may

19

^{th}may + 7 days = Saturday = 26

^{th}may

= Answer = 26

^{th}may

9. What was the day of the week on 10^{th} March 1996?

a) Friday

b) Saturday

c) Thursday

d) Sunday

Explanation:

$$\eqalign{ & \frac{{10 + 4 + 96 + 24 + 0}}{7} \cr & = \frac{{134}}{7} \cr & = 1 \cr & = {\text{Sunday}} \cr} $$

10. What day of the week will 22 Apr 2222 be?

a) Monday

b) Wednesday

c) Tuesday

d) Thursday

Explanation:

22 Apr 2222 = (2221 years + period from 1-Jan-2222 to 22-Apr-2222)

We know that number of odd days in 400 years = 0

Hence the number of odd days in 2000 years = 0 (Since 2000 is a perfect multiple of 400)

Number of odd days in the period 2001-2200

= Number of odd days in 200 years

= 5 x 2 = 10 = 3

(As we can reduce perfect multiples of 7 from odd days without affecting anything)

Number of odd days in the period 2201-2221

= 16 normal years + 5 leap years

= 16 x 1 + 5 x 2 = 16 + 10 = 26 = 5 odd days

Number of days from 1-Jan-2222 to 22 Apr 2222

= 31 (Jan) + 28 (Feb) + 31 (Mar) + 22(Apr) = 112

112 days = 0 odd day

Total number of odd days = (0 + 3 + 5 + 0) = 8 = 1 odd day

1 odd days = Monday

Hence 22 Apr 2222 is Monday